下列叙述NaS溶液的质子条件，正确的是（）A[H+]+[HS–]+[HS]=[OH–]B[H+]+[Na+]=[HS–]+[S]+[OH–]C[H+]+[Na+]=[HS–]+[S]+[OH–]D[H+]+[HS–]+[HS]=[OH–]